def fibnacci(n):
    """
    计算斐波那契数列的第 n 项值
    1, 1, 2, 3, 4, 5, 8, 13...
    fibnacci(n) = fibnacci(n-2) + fibnacci(n-1)
    :param n: 第 n 项元素
    :return: 第 n 项元素的值
    """
    if n == 1 or n == 2:
        return 1
    else:
        return fibnacci(n - 2) + fibnacci(n - 1)


if __name__ == '__main__':
    print(fibnacci(60))
